Hitting the road or friendly skies for a Labor Day Weekend getaway? You’re not alone.

The holiday, which many celebrate as the unofficial end of summer, is a popular time for Americans to take a vacation. But if you don’t like crowds, you probably shouldn’t head to the City by the Bay.

Hotel search website trivago reports that San Francisco is the most popular destination for travelers looking to head out of town for the historic holiday. Rounding out the top five: Orlando, Las Vegas, Los Angeles, and New York City.

 

Not only will you have to battle crowds in popular destinations like New York and Altantic City, but finding cheap accommodation in those cities might be tough as well. Trivago says a standard double hotel room in the U.S. will cost an average $132 over the Labor Day weekend. But in cities like Milwaukee, Ocean City, Md.,  New York and Key West, Fla., trivago says hotel prices are exceptionally steep. In Milwaukee, hotel prices for the long weekend average around $358 — in part because the Wisconsin city will celebrate the 110th Anniversary of Harley-Davidson Motorcycles. While inKey West, the 4th annual Key West Brewfest will take place.  

If you’ve got an itch for one last summer hurrah, but are hoping not to spend a fortune on accommodation, trivago says great hotel deals can be found in the South and Midwest over the long weekend. In Savvanah, Ga., hotels can be found for an average price of $122 and in Williamsburg, Va., a standard double room will set you back $125/night.

One state Labor Day travelers might want to explore if they’re seeking affordable accommodation is Florida, where Daytona Beach, Orlando and Tampa rank among the top cities with relatively low hotel prices.